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Configuration = 10
cycles = (10 7 4 8 6)(9 3 1 5 2)

a = 3, b = 5, c = 9
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cycles = (10 5 8 6 4)(9 2)(7)(3 1)

a = 5, b = 8, c = 10
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cycles = (10 8 4)(9)(7)(6 2)(5)(3 1)

a = 2, b = 3, c = 6
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cycles = (10 8 3)(9)(7)(6 1 2)(5)(4)

a = 1, b = 2, c = 6
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cycles = (10 8 2)(9)(7)(6)(5)(4)(3)(1)